Optimal. Leaf size=110 \[ \frac{b e^2 n \text{PolyLog}\left (2,-\frac{d}{e x}\right )}{d^3}-\frac{e^2 \log \left (\frac{d}{e x}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{d^3}+\frac{e \left (a+b \log \left (c x^n\right )\right )}{d^2 x}-\frac{a+b \log \left (c x^n\right )}{2 d x^2}+\frac{b e n}{d^2 x}-\frac{b n}{4 d x^2} \]
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Rubi [A] time = 0.170924, antiderivative size = 135, normalized size of antiderivative = 1.23, number of steps used = 7, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {44, 2351, 2304, 2301, 2317, 2391} \[ -\frac{b e^2 n \text{PolyLog}\left (2,-\frac{e x}{d}\right )}{d^3}+\frac{e^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 b d^3 n}-\frac{e^2 \log \left (\frac{e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{d^3}+\frac{e \left (a+b \log \left (c x^n\right )\right )}{d^2 x}-\frac{a+b \log \left (c x^n\right )}{2 d x^2}+\frac{b e n}{d^2 x}-\frac{b n}{4 d x^2} \]
Antiderivative was successfully verified.
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Rule 44
Rule 2351
Rule 2304
Rule 2301
Rule 2317
Rule 2391
Rubi steps
\begin{align*} \int \frac{a+b \log \left (c x^n\right )}{x^3 (d+e x)} \, dx &=\int \left (\frac{a+b \log \left (c x^n\right )}{d x^3}-\frac{e \left (a+b \log \left (c x^n\right )\right )}{d^2 x^2}+\frac{e^2 \left (a+b \log \left (c x^n\right )\right )}{d^3 x}-\frac{e^3 \left (a+b \log \left (c x^n\right )\right )}{d^3 (d+e x)}\right ) \, dx\\ &=\frac{\int \frac{a+b \log \left (c x^n\right )}{x^3} \, dx}{d}-\frac{e \int \frac{a+b \log \left (c x^n\right )}{x^2} \, dx}{d^2}+\frac{e^2 \int \frac{a+b \log \left (c x^n\right )}{x} \, dx}{d^3}-\frac{e^3 \int \frac{a+b \log \left (c x^n\right )}{d+e x} \, dx}{d^3}\\ &=-\frac{b n}{4 d x^2}+\frac{b e n}{d^2 x}-\frac{a+b \log \left (c x^n\right )}{2 d x^2}+\frac{e \left (a+b \log \left (c x^n\right )\right )}{d^2 x}+\frac{e^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 b d^3 n}-\frac{e^2 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{d^3}+\frac{\left (b e^2 n\right ) \int \frac{\log \left (1+\frac{e x}{d}\right )}{x} \, dx}{d^3}\\ &=-\frac{b n}{4 d x^2}+\frac{b e n}{d^2 x}-\frac{a+b \log \left (c x^n\right )}{2 d x^2}+\frac{e \left (a+b \log \left (c x^n\right )\right )}{d^2 x}+\frac{e^2 \left (a+b \log \left (c x^n\right )\right )^2}{2 b d^3 n}-\frac{e^2 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{d^3}-\frac{b e^2 n \text{Li}_2\left (-\frac{e x}{d}\right )}{d^3}\\ \end{align*}
Mathematica [A] time = 0.197236, size = 124, normalized size = 1.13 \[ -\frac{4 b e^2 n \text{PolyLog}\left (2,-\frac{e x}{d}\right )+\frac{2 d^2 \left (a+b \log \left (c x^n\right )\right )}{x^2}+4 e^2 \log \left (\frac{e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )-\frac{4 d e \left (a+b \log \left (c x^n\right )\right )}{x}-\frac{2 e^2 \left (a+b \log \left (c x^n\right )\right )^2}{b n}+\frac{b d^2 n}{x^2}-\frac{4 b d e n}{x}}{4 d^3} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.158, size = 689, normalized size = 6.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{2} \, a{\left (\frac{2 \, e^{2} \log \left (e x + d\right )}{d^{3}} - \frac{2 \, e^{2} \log \left (x\right )}{d^{3}} - \frac{2 \, e x - d}{d^{2} x^{2}}\right )} + b \int \frac{\log \left (c\right ) + \log \left (x^{n}\right )}{e x^{4} + d x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \log \left (c x^{n}\right ) + a}{e x^{4} + d x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 123.158, size = 246, normalized size = 2.24 \begin{align*} - \frac{a}{2 d x^{2}} + \frac{a e}{d^{2} x} - \frac{a e^{3} \left (\begin{cases} \frac{x}{d} & \text{for}\: e = 0 \\\frac{\log{\left (d + e x \right )}}{e} & \text{otherwise} \end{cases}\right )}{d^{3}} + \frac{a e^{2} \log{\left (x \right )}}{d^{3}} - \frac{b n}{4 d x^{2}} - \frac{b \log{\left (c x^{n} \right )}}{2 d x^{2}} + \frac{b e n}{d^{2} x} + \frac{b e \log{\left (c x^{n} \right )}}{d^{2} x} + \frac{b e^{3} n \left (\begin{cases} \frac{x}{d} & \text{for}\: e = 0 \\\frac{\begin{cases} \log{\left (d \right )} \log{\left (x \right )} - \operatorname{Li}_{2}\left (\frac{e x e^{i \pi }}{d}\right ) & \text{for}\: \left |{x}\right | < 1 \\- \log{\left (d \right )} \log{\left (\frac{1}{x} \right )} - \operatorname{Li}_{2}\left (\frac{e x e^{i \pi }}{d}\right ) & \text{for}\: \frac{1}{\left |{x}\right |} < 1 \\-{G_{2, 2}^{2, 0}\left (\begin{matrix} & 1, 1 \\0, 0 & \end{matrix} \middle |{x} \right )} \log{\left (d \right )} +{G_{2, 2}^{0, 2}\left (\begin{matrix} 1, 1 & \\ & 0, 0 \end{matrix} \middle |{x} \right )} \log{\left (d \right )} - \operatorname{Li}_{2}\left (\frac{e x e^{i \pi }}{d}\right ) & \text{otherwise} \end{cases}}{e} & \text{otherwise} \end{cases}\right )}{d^{3}} - \frac{b e^{3} \left (\begin{cases} \frac{x}{d} & \text{for}\: e = 0 \\\frac{\log{\left (d + e x \right )}}{e} & \text{otherwise} \end{cases}\right ) \log{\left (c x^{n} \right )}}{d^{3}} - \frac{b e^{2} n \log{\left (x \right )}^{2}}{2 d^{3}} + \frac{b e^{2} \log{\left (x \right )} \log{\left (c x^{n} \right )}}{d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \log \left (c x^{n}\right ) + a}{{\left (e x + d\right )} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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